3(2x-3)^2=4x(3-2x)

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Solution for 3(2x-3)^2=4x(3-2x) equation: 



3(2x-3)^2=4x(3-2x)

We move all terms to the left:

3(2x-3)^2-(4x(3-2x))=0

We add all the numbers together, and all the variables

3(2x-3)^2-(4x(-2x+3))=0



We calculate terms in parentheses: -(4x(-2x+3)), so:

4x(-2x+3)

We multiply parentheses

-8x^2+12x

Back to the equation:

-(-8x^2+12x)



We get rid of parentheses

8x^2-12x+3(2x-3)^2=0

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